acceleration of 0.60 musee. You arive at the station evactly 4.00 seconds anter
ID: 1658526 • Letter: A
Question
acceleration of 0.60 musee. You arive at the station evactly 4.00 seconds anter the train leaves and you immediately start running after the train with a constant velocity of 8.50 m/sec. a. How long after the train leaves the station do you catch up with the train? b. How far from the train station do you catch up with the train? 15. You are rushing to the train station to catch your moming commute. The train leaves the train station from rest with an id you have to run in order to catch up with the train?Explanation / Answer
a) v = v0 + at
d = 1/2 a t2 = 1/2 * 0.600 t2 = 0.300 t2
you arrive at station exactly 4 seconds
d = v * (t - 4) = 8.5 (t - 4) = 8.5 t - 34
equating above equations
0.300 t2 = 8.5 t - 34
0.300 t2 - 8.5 t + 34 = 0
t = 4.82 s, t = 23.5 s
b) d = 1/2 a t2 = 1/2 * 0.600 * 4.822= 6.96 m
d = 8.5 (23.5 - 4) = 166 m
c) 0.300 t2 = v (t - 4)
0.300 t2 - vt + 4 = 0
v2 - (4 * 0.3 * 4v) = 0
v = 4.8 m/s
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