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Chrome File Edit View History Bookmarks People Window Help D 52%. Tue Sep 26 19:

ID: 1658539 • Letter: C

Question

Chrome File Edit View History Bookmarks People Window Help D 52%. Tue Sep 26 19:35 a eoo Math 250: Calculus I e Physics question l Chegg.com × y l«Kudu CSecure https://kudu.com Apps join.me V, Leo's Remote SupporiGS gold award Kudu Question 3 An electron enters a region between two large parallel plates made of aluminum separated by a distance of 2.0 cm and kept at a potential difference of 200 V. The electron enters through a small hole in the negative plate and moves toward the positive plate. At the time the electron is near the negative plate, its speed is 4.0 x 10% m/s. Assume the electric field between the plates to be uniform, and find the speed of electro at 1.5 cm from the negative plate d=2cm, V = 200 V UFF Goo 017....MM Scroll to Back Top 26

Explanation / Answer

electric field between plates

E = V/d = 200/0.02 = 1*10^4 V/m

now force on electron

F = eE = -1.6*10^-19*10^4 = - 1.6*10^-15 N

-ve sign means force acts opposite to the direction of electric field

now acceleration of electron

a = F/m = 1.6*10^-15/(9.1*10^-31) = 0.175*10^16 m/s^2

now v^2 = u^2 + 2aS

=> (v)^2 = (4*10^5)^2 + 2*0.175*10^16*0.015 = 5266*10^10

=> v = 72.56*10^5 m/s = 7.256*10^6 m/s OPTION (c)

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