7. O -1 points SerCP11 16.P.023. My Notes Ask Your Teacher In Rutherford\'s famo

Question

7. O -1 points SerCP11 16.P.023. My Notes Ask Your Teacher In Rutherford's famous scattering experiments that I ed to the planetary model of the atom, alpha particles (having charges of +2e and masses of kg) were fired toward a gold nucleus with charge +79e. An alpha particle, initially very far from the gold nucleus, is fired at 2.22 × 107 m/s directly toward the nucleus, as in the figure below. How close does the alpha particle get to the gold nucleus before turning around? Assume the gold nucleus remains stationary 79e 2e Need Help? ReadWach

Explanation / Answer

The problem can be solved using conservation of energy

initial energy of alpha particle = kinetic energy = (1/2)*6.64*10-27*(2.22*107)2 = 16.362288*10-13 Joule

When the alpha particle is closest to gold nucleus,the total energy of alpha particle=electric potential energy(because kinetic energy is zero)

16.362288*10-13 = 9*109*(2*1.6*10-19)*(79*1.6*10-19)/d

d = 2.2248*10-14 m

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