Need help!!!!! True Explain the reason using equations False or give a supportiv

Question

Need help!!!!! True Explain the reason using equations False or give a supportive/ opposite example If the magnitude of velocity is decreasing, the magnitude of acceleration cannot be increasing. If the magnitude of velocity is increasing, the magnitude of acceleration cannot be decreasing. If the v-t graph as shown on the right, the particle's acceleration is decreasing. If the v-t graph is a horizontal line, the particle is staying at rest If a particle is moving in circle at a constant speed, the acceleration of the particle is zero. If a particle is moving along a curvature, the actual direction ofthe radial component ofthe acceleration can point towards or away from the coordinate's origin If a particle is moving along a curvature, the actual direction of the normal component of the acceleration can point towards or away from the center of the curvature. Resultant external force must be in the same direction as the motion. |(vel-are 2for Resultant external force must be in the same direction as the acceleration. If v = 0, the resultant external force exerted on the particle at that moment must be zero.

Explanation / Answer

1. False, acceleration= change in velocity/time taken

That is magnitude of acceleration depends only on the change in velocity and the time taken for the change and it is independent of whether velocity increased our decreased.

2. False, Same reason mentioned in (1)

3. False, From the plot the velocity decreasing linearly with respect to time, let it be v=At+B then acceleration a=dv/dt= A which is a constant.

4. False, If v-t plot is a horizontal line then velocity=v=constant then acceleration=a=dv/dt=0. Hence the particle moves with uniform velocity but not at rest.

5. False, In circular motion with constant speed, only tangential acceleration is zero but not radial acceleration. Due to this acceleration the particle will feel centrifugal force.

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