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Glven:q-1.60 x 10-1C, q2-_1.60 × 10-1,C, & 2a-1.00 x 10-10m (a) A sphere of radi

ID: 1659131 • Letter: G

Question

Glven:q-1.60 x 10-1C, q2-_1.60 × 10-1,C, & 2a-1.00 x 10-10m (a) A sphere of radius 2.0 encloses a dipole. Find the electric flux through the sphere. (Hint: what is the total charge 91 enclosed in the sphere?) 2a (b) Does your answer depend on the radius of the sphere? (c) Does you answer require that the sphere be centered at the origin? (d) Does the flux depend on the distance between the two charges as long as the charges remain enclosed? (e) Does the flux depend on the shape of the enclosing surface?

Explanation / Answer

Given,

q1 = 1.6 x 10^-19 C ; q2 = -1.6 x 10^-19 C

2a = 1 x 10^-19 m

From Gauss law we know that the electric flux for a closed surface is:

phi = Q(enclosed)/e0

for the given case,

Q(enclosed) = q1 + q2

Q(enclosed) = 1.6 x 10^-19 C - 1.6 x 10^-19 C = 0

Hence, flux = 0

b)No, it did not depend on the radius

c)No, this assumption is not needed.

d)No, the flux is independent of the separation of the charges

e)When the flux is caluclated using,

phi = EA

it depends on the geometry of the surface.

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