When a parachute opens, the air exerts a large drag force on it. This upward for

Question

When a parachute opens, the air exerts a large drag force on it. This upward force is initially greater than the weight of the sky diver and, thus, slows him down. Suppose the weight of the sky diver is 953 N and the drag force has a magnitude of 1100 N. The mass of the sky diver is 97.2 kg. Take upward to be the positive direction. What is his acceleration, including sign? When a parachute opens, the air exerts a large drag force on it. This upward force is initially greater than the weight of the sky diver and, thus, slows him down. Suppose the weight of the sky diver is 953 N and the drag force has a magnitude of 1100 N. The mass of the sky diver is 97.2 kg. Take upward to be the positive direction. What is his acceleration, including sign?

Explanation / Answer

here,

mass of the skydiver , m = 97.2 kg

the drag force , Fd = 1100 N

the weight of sky diver , W = - 953 N

the accelration , a = net force /effective mass

a = ( 1100 - 953) /97.2 m/s^2

a = 1.51 m/s^2

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