(8%) Problem 7: Two blocks are pressed together as shown. The blocks have masses
ID: 1659453 • Letter: #
Question
(8%) Problem 7: Two blocks are pressed together as shown. The blocks have masses mn = 5.45 kg and me.-10.1 kg. The static coefficient of friction between the two blocks is 0.47. The tabletop is frictionless. A rightward force, F, is exerted on Block 2 frictionless tabletop Calculate the minimum force (in Newtons) required to keep Block 1 from slipping along Block 2 Grade Summary 0% 100% Potential Attempts remaining: 6 cotanasinacos0 atan) acotan)sinh0 cosh0 tanh) cotanh0 oDegrees Radians % per attempt) detailed view 12 3 0 CLEAR Submit I give up! Hints: 0 for a 0% deduction. Hints Feedback: 0% deduction per feedback.Explanation / Answer
here,
m1 = 5.45 kg
m2 = 10.1 kg
us = 0.47
a)
let the minimum force be F
equating the forces vertically
m1 * g - frcitional force = 0
5.45 * 9.81 - F * us = 0
F * 0.47 = 5.45 * 9.81
F = 113.8 N
the minimum force required is 113.8 N
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.