002 (part 1 of 6) 10.0 points A plastic rod 1.5 m long is rubbed all over with W

Question

002 (part 1 of 6) 10.0 points A plastic rod 1.5 m long is rubbed all over with Wool, and acquires a charge O (see the figure below). We choose the center of the rod to be the origin of our coordinate system, with the r axis extending to the right, the y axis extending up, and the z axis out of the page. In order to calculate the electric field at location A, which is at f-4 × 10-8 C iA = 0.5, 0, 0) m, we divide the rod into 8 pieces, and approxi mate each piece as a point charge located at the center of the piece. 2 6 7 What is the length of one of these pieces? Use the value of k 8.98755 × 109 N-m2/C2. Answer in units ofm.

Explanation / Answer

(4)
For the electric field you need to use this equation

E = (1/4*phi*e0)*(q/mode r^2 )*r^

find the r = (0.5 ,0 ,0 ) - (0 , 0.09375, 0)

r = (0.5 , -0.09375 , 0)

find the magnitude
mode r = sqroot(0.5^2 + (-0.09375))

= 0.508713

r^ = r vector / mode r vector

= (0.5 , - 0.09375 , 0) / (0.508713)

=(0.982872 , -0.184288)

Then you plug everything into this equation

E = (1/4*phi*e0)*(q/mode r^2 )*r^

= (9*10^9)*( -1*10^-8/ .508713^2)*(0.982872 , -0.184288)

= (- 34.1817 , 64.0905 , 0 )

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