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Note: Alright, for the following, I got the first half of this problem dealt wit

ID: 1659842 • Letter: N

Question

Note: Alright, for the following, I got the first half of this problem dealt with. But I'm not so sure on how to do Parts E,F,G and H. Please show me the proper steps to solve them, and be sure to mark your final answers by circling them. Thanks.

Item 11 Part A If Fi 14.0 N and F2 21.0 N, find the magnitude of the net force on the object for (a) The two forces Fi and F2 shown in the figure (Figure 1) (looking down) act on a 17.0-kg object on a frictionless tabletop | F= 252 N Submit My Answers Give Up Correct Significant Figures Feedback: Your answer 25.239 N was either rounded differently or used a different number of significant figures than required for this part. If you need this result for any later calculation in this item, keep all the digits and round as the final step before submitting vour answer Part B Find the direction of the net force on the object for (a) = 236 ° from the +x axis Submit Mv Answers Give Up Figure 1 |of 1 Correct Part c Find the magnitude of the acceleration of the object for (a) 120 a= 1.48 m/s2 Submit My Answers Give Up Correct Significant Figures Feedback: Your answer 1.482 m/s2 was either rounded differently or used a different number of significant figures than required for this part.

Explanation / Answer

partE] Resulltant R = sqrt(F1^2 + F2^2 + 2F1*F2 cos 120 degree)

= sqrt(14^2+21^2+2*14*21* cos 120 degree )

= 18.52 N

partF] x component of resultant = 14 cos 30 degree

angle theta = arccos(14 cos 30 degree /18.52)

= 49.1 degree

partE] a = F/m = 18.52/17 = 1.09 m/s^2

partF] theta =49.1 degree same as force direction

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