Inverse Trigonometric Functions 10of10 from sreet eveltea lsating docik Constant

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Inverse Trigonometric Functions 10of10 from sreet eveltea lsating docik Constants palcy for werker safe Students who successfully complete this primer will be able to: . Analyze physical quantities related through the properties of a right triangle to obtain expressions for angles in terms of inverse trigonometric functions Use a calculator to evaluate the numerical value of angles using inverse trigonometric functions Part D A force is applied to a block sliding along a surface (Figure 2). The magnitude of the force is 15 N, and the horizontal component of the force is 4.5 N. At what angle (in degrees) above the horizontal is the force directed? Before working on this primer, you may need to review: Express your answer to two significant figures Figure 1 of 2 > View Available Hint(s) Centralburg map grocery store Submit Previous Answers Request Answer an = 4 blocks Incorrect, Try Again: 4 attempts remaining post de-3 blocks Return to Assignment Provide Feedback

Explanation / Answer

According to the given problem,

Using the vector notation,

The horizontal component of a force acting on a block is,

Fx = Fcos

From above problem, given Fx = 4.5N and F is 15N

Substitute the values to get ,

4.5 = 15cos

cos = 0.3

= 72.54o

I hope you understood the problem, If yes rate me! or else fell free to comment.

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