8. Due hurricane are to the properties of angular momentum, the winds with the g
ID: 1661829 • Letter: 8
Question
8. Due hurricane are to the properties of angular momentum, the winds with the greatest velocities in a a. b. c. d. Located at the outer edge of the storm Located near the eye of the storm Located in the eye of the storm All wind velocities in the storm are the same II. PROBLEM SOLVING 9. Determine the momentum of a 621 g basebail travelling at 40.0 m/s. 10. A force with a magnitude of 571 N is used to stop an object with a mass of 63 kg moving at a velocity of 163 m/s. How long will it take to bring the object to a stop? 11. A force of 201 N acts on a 7.3 kg bowling ball for.38 s. What is the ball's change in momentum? 12. A tennis ball is thrown toward a wall with a velocity of 29.5 m/s. The ball bounces back off the wall with a velocity of 21.2 m/s. What is the impulse on the tennis ball? M . 23y 5 13. A 2650 kg truck travelling at 19,0 m/s collides with an 835 kg car travelling at 8.00 m/s in the same direction. After colliding, they move off together in the same direction in which they were both originally travelling. What is the final velocity of the wreckage? 14. Two lab carts are pushed together with a spring mechanism compressed between them Upon release of the spring, the 8.0 kg cart moves one way with a speed of.30 m/s, while the 10.0 kg cart moves in the opposite direction. What is the velocity of the 10.0 kg cart? 15. The velocity of a 651 kg car is changed from 12.0 m/s to 45.0 m/s in 55.0 s by a constant force. What is the resulting change in momentum of the car? What is the magnitude of the force?Explanation / Answer
(8)Due to the properties of angular momentum, the winds with the greatest velocities in a Hurricane are
(b) Located near the eye of the storm
Explanation:
According to the law of conservation of angular momentum, if the sum of all the external torques acting on an object is zero, the total angular momentum remains constant.
m v r= constant
m= mass of the object
v= velocity
r=perpendicular distance of the object from the axis of rotation
since m is constant, we can say
vr= constant
v1 r1 = v2 r2
when we move closer to the center(eye) of the hurricane, distance r decreases. So the velocity increases.
so the velocity of the winds near the eye of the storm will be greatest.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.