MESSAGEMY INSTRUCTOR FULL SCRttN PRINTER VERSION BACK NEXT Chapter 07, Problem 1

Question

MESSAGEMY INSTRUCTOR FULL SCRttN PRINTER VERSION BACK NEXT Chapter 07, Problem 10 Consult Interactive Solution 7.10 for a review of problem-solving skills that are involved in this problem. A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a velocity of +16.0 m/s, while the exiting water stream has a velocity of -16.0 m/s. The mass of water per second that strikes the blade is 35.0 kg/s. Find the magnitude of the average force exerted on the water by the blade. Stationary hurbine blade =+16.0 m/s Number Units the tolerance is +/-2% LINK TO TENT

Explanation / Answer

Initial Velocity V1 = 16 m/sec, Final velocity V2 = -16 m/sec. So change in velocity is dV = V1 - V2 = 32 m/sec

Mass of water per second striking is M = 35 kg/sec. By definition rate of momentum change is Force.

So force exerted is F = M(dV) = (35 x 32) kg.m/sec2 , So force F = 1120 N .

Related Questions

Navigate

• Browse (All)
• Browse M
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.