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Question

                  B---------------------------------------------------------------------------------------
                                                 90.0 m
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|                                                             A ----------------------------------------------------------|
|                                                                                          50.0m                                                  |

In the Tacoma Narrows bridge, a wind force was applied from below,since the bridge decking could not counter that force; the bridgeencountered torque at its abutments. In this case, the forceat A is 1,500 N. How much force would you need to apply at Bto counter the torque on the right hand pier?
           
I am stuck and don't know where to start! Please help!

Explanation / Answer

From principle of moments when the system is in equilibrium the net torque qctingon the system is zero        1500(50m) = F(90m)       therefore          F = 7500 /90 = 83.33N   

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