(a) A star\'s temperature is 4951 K.According to the Stefan-Boltzmann law, how m
ID: 1662289 • Letter: #
Question
(a) A star's temperature is 4951 K.According to the Stefan-Boltzmann law, how much energy is radiatedinto space per second by each square meter of the star's surface?---------J
(b) If the star's radius is 641,000 km, what is the totalpower output of the star?
--------W
(a) A star's temperature is 4951 K.According to the Stefan-Boltzmann law, how much energy is radiatedinto space per second by each square meter of the star's surface?
---------J
(b) If the star's radius is 641,000 km, what is the totalpower output of the star?
--------W
Explanation / Answer
From stefan Boltzmann law
Q= T4
= (5.67*10-8 ) (4951K)4 = 34*106J
(b) Q/t = T4 A= T4 ( r2 ) =(5.67*10-8 ) (4951)4 ( 3.14*6.41*108 )
solve it
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