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At amusement parks, there is a popular ride where the floor of arotating cylindr

ID: 1662837 • Letter: A

Question

At amusement parks, there is a popular ride where the floor of arotating cylindrical room falls away, leaving the backs of theriders "plastered" against the wall. Suppose the radius ofthe room is 3.30m and the speed of the wall is 10.0m/s when thefloor falls away. a) What is the source of the centripetalforce acting on the riders? b) How much centripetal forceacts on a 55.0kg rider? c)What is the minimum coefficient ofstatic friction that must exist between a rider's back and thewall, if the rider is to remain in place when the floor dropsaway?
answer: b) 1670N , c) 0.323

Explanation / Answer

a) supporting force due to the wall b) mv2/r = 55.0*10.02/3.30 = 1670 N c) mg = N = mv2/r = gr/v2 = 9.8*3.30/10.02 =0.323

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