At amusement parks, there is a popular ride where the floor of arotating cylindr
ID: 1662837 • Letter: A
Question
At amusement parks, there is a popular ride where the floor of arotating cylindrical room falls away, leaving the backs of theriders "plastered" against the wall. Suppose the radius ofthe room is 3.30m and the speed of the wall is 10.0m/s when thefloor falls away. a) What is the source of the centripetalforce acting on the riders? b) How much centripetal forceacts on a 55.0kg rider? c)What is the minimum coefficient ofstatic friction that must exist between a rider's back and thewall, if the rider is to remain in place when the floor dropsaway?answer: b) 1670N , c) 0.323
Explanation / Answer
a) supporting force due to the wall b) mv2/r = 55.0*10.02/3.30 = 1670 N c) mg = N = mv2/r = gr/v2 = 9.8*3.30/10.02 =0.323
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.