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I am completely lost on this question. I feel that thereisn\'t enough informatio

ID: 1662987 • Letter: I

Question

I am completely lost on this question. I feel that thereisn't enough information given. I would love somehelp.   Thanks in advance!

Under constant pressure, the temperature of 1.60 mol of an ideal monatomic gas is raised14.0 K. (a) What is the work W done by thegas?
1 J

(b) What is the energy transferred as heat Q?
2 J

(c) What is the change Eint in theinternal energy of the gas?
3 J

(d) What is the change K in the average kineticenergy per atom?
4 J (a) What is the work W done by thegas?
1 J

(b) What is the energy transferred as heat Q?
2 J

(c) What is the change Eint in theinternal energy of the gas?
3 J

(d) What is the change K in the average kineticenergy per atom?
4 J

Explanation / Answer

since it has constant pressure this means the process isisobaric (check the top of page 529). Also see example 19-7 on thebottom of page 522 to help with this problem. a) W = pV = nRT = 1.6*8.31*14 = 186 J b) Q=nCpT
Cp = Cv + R; Cv=3/2R for any monotomic gas Q = n(Cv + R)T = 1.6*(2.5*8.31)(14) = 465 J c)Eint =Q-W = 465 - 186 =279J d) K = 3/2kT = 3/2 * 1.38*10^-23 * 14 = 2.90*10^24J