An indestructible bullet 2.00 cm long is fired straight through aboard that is 1

Question

An indestructible bullet 2.00 cm long is fired straight through aboard that is 10.0 cm thick. The bullet strikes the board with aspeed of 480 m/s and emerges with a speedof 295 m/s. (To simplify, assume that thebullet accelerates only while the front tip is in contact with thewood.) (a) What is the average acceleration of thebullet through the board?
Enter anumber. m/s2

(b) What is the total time that the bullet is in contact with theboard?
Enter anumber. s

(c) What thickness of board (calculated to 0.1 cm) would it take tostop the bullet, assuming that the acceleration through all boardsis the same?
Enter anumber. cm (a) What is the average acceleration of thebullet through the board?
Enter anumber. m/s2

(b) What is the total time that the bullet is in contact with theboard?
Enter anumber. s

(c) What thickness of board (calculated to 0.1 cm) would it take tostop the bullet, assuming that the acceleration through all boardsis the same?
Enter anumber. cm Enter anumber. Enter anumber. Enter anumber.

Explanation / Answer

So, to start, the average acceleration is going to be the distance/time^2 distance is 10 cm, the time (if we assume constant acceleration(being that they don't say acceleration is proportional tovelocity, i think constant acceleration is reasonable to assume))is going to be the distance divided by the average velocity or: t = 10/((480+295)/2) with that average acceleration is .1/t^2 Keeping the same average acceleration, just do, D = v0*t -1/2*a*t^2 in conjunction with t =v/a                where v is v average which is (0+295)/2

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