Density, density,density . (a) A charge-325 e is uniformly distributed along a c
ID: 1664835 • Letter: D
Question
Density, density,density. (a) A charge-325e is uniformly distributed along a circular arcof radius 7.10 cm, which subtends an angle of 69o. Whatis the linear charge density along thearc? (b) A charge -325e isuniformly distributed over one face of a circular disk of radius2.60 cm. What is the surface charge density over thatface? (c) A charge-325e is uniformly distributed over the surface of asphere of radius 4.30 cm. What is the surface charge density overthat surface?(d) A charge-325e is uniformly spread through the volume of asphere of radius 2.00 cm. What is the volume charge density in thatsphere? Numbers different from book, please give answer.Explanation / Answer
Given : The charge density is = Q/LL= length of arc = 2r (69o/180o)
Q= -325e = -320 (1.602 x 10-19C )
r = radius = 7.10 cm = 0.071m
= [-320 (1.602 x 10-19 C)] / [2 (.071m)(69o/180o) ]
= ------- C/m
The charge density is = Q/L
L= length of arc = 2r (69o/180o)
Q= -325e = -320 (1.602 x 10-19C )
r = radius = 7.10 cm = 0.071m
= [-320 (1.602 x 10-19 C)] / [2 (.071m)(69o/180o) ]
= ------- C/m
B ) r = 2.60 cm = 0.0260 = q / A [ A = r2 ] = -325*(1.620*10-19) /[*(.0260)2] = ------ C / m2 C ) r = 4.30 cm =0.0430 Surface chrage density s= q / 4A [ A = r2 ] =q / 4 r2 = 325*(1.620*10-19) /[(4/3)*(.0430)2] = 325*(1.620*10-19) /[(4/3)*(.0430)2] D ) r =2.0 cm = 0.02 Volume chragedensity s= q / 4/3r3 = -325*(1.620*10-19)*3 /[(4)*(.020)3] = ---------- Solve it Volume chragedensity s= q / 4/3r3 = -325*(1.620*10-19)*3 /[(4)*(.020)3] = ---------- Solve it = ----- C / m2
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