NOTE: the answers from the book lists: 3 (A). p m = p f =.6 , q m = q f = .4 (B)
ID: 166523 • Letter: N
Question
NOTE: the answers from the book lists: 3 (A). pm = pf =.6 , qm = qf = .4 (B). AA = 0.36, Aa= 0.48, aa= 0.16 , I would like to know the steps to get these answers and explanations, thank you!
3) Let the frequencies of a pair of autosomal alleles A and a be represented by pm and gm in males and by pf and gf in females. given gf = .6 and gm= .2, (A) determine the equilibrium gene frequencies in both sexes after one generation of random mating, and (B) give the genotypic frequencies expected in the second random mating
Explanation / Answer
Answer (A)
The equilibrium gene frequencies in both sexes after one generation of random
if the other allele be qm and qf for females.
So the frequencies would be pm=pf=gf=0.6
qm=qf=1-pm=1-.06=0.4
Answer (B)
Genetypic freqencies in second random mating
This mating would be between AA and aa, so the offspring will be AA, 2Aa, aa
As per Hardy-Weinberg principal:
p2+2pq+q2=1
AA+2Aa+aa=1
Here AA=0.6*0.6=0.36
Aa=0.6*0.4=0.24 So, 2Aa=0.24*2=0.48
aa=0.4*0.4=0.16
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