A parallel plate capacitor has plates of area 3.45 x10 -4 m 2 . What plate seper

Question

A parallel plate capacitor has plates of area 3.45 x10-4 m2. What plate seperation isrequired if the capacitance is to be 1630 pF? Assume that thespace between the plates is filled with a) air (dielectric constant for air is 1.00059) b) paper (dielectric constant for paper is 3.7) A parallel plate capacitor has plates of area 3.45 x10-4 m2. What plate seperation isrequired if the capacitance is to be 1630 pF? Assume that thespace between the plates is filled with a) air (dielectric constant for air is 1.00059) b) paper (dielectric constant for paper is 3.7)

Explanation / Answer

A parallel plate capacitor has plates of area 3.45 x10-4 m2. What plate separation isrequired if the capacitance is to be 1630 pF? Assume that thespace between the plates is filled with a) air (dielectric constant for air is 1.00059)
capacitance=kAo/d
so d= kAo/C=
1.00059*3.45 x10-4*8.84*10-12/1630*10-12=0.0187*10-4m
b) paper (dielectric constant for paper is 3.7)
d= kAo/C=
3.7*3.45 x10-4*8.84*10-12/1630*10-12=0.0692*10-4m

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