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A parallel-plate capacitor is made by placing polyethylene ( =2.3) between two s

ID: 1665671 • Letter: A

Question

A parallel-plate capacitor is made by placing polyethylene ( =2.3) between two sheets of aluminum foil. The area of eachsheet of aluminum foil is 410 cm2, and the thickness ofthe polyethylene is 0.5 mm. The permittivity of free space is8.85 × 1012 C2/N · m2. Find thecapacitance. Answer in units of nF. A parallel-plate capacitor is made by placing polyethylene ( =2.3) between two sheets of aluminum foil. The area of eachsheet of aluminum foil is 410 cm2, and the thickness ofthe polyethylene is 0.5 mm. The permittivity of free space is8.85 × 1012 C2/N · m2. Find thecapacitance. Answer in units of nF.

Explanation / Answer

      Area of a parallel platecapacitor is A = 410 cm2 = 410*10-4 m2                      seperated by a distance d = 0.5 mm = 0.5*10-3 m                                 dielectric constant k = 2.3                              Capacitance of a Capacitor is C = k 0A / d                                                                     = 2. 3* 8.85*10-12 C2 /N m2 * 410 *10-4 m2 / 0.5 *10-3m                                                                     = 1669 nF
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