I need to find the Equiv. Resistance of N pieces connected inparallel. I calcula
ID: 1665962 • Letter: I
Question
I need to find the Equiv. Resistance of N pieces connected inparallel. I calculated that 1 piece is = R1*n^-1 and I know that Ineed to add all of these to get the R eq. but because its aconceptual question and I have no numbers I can't figure out away to express this. I've already tried to put(R1*n^-1) as an answer but it tells me it the answerdoesn't contain the variable . Please help!!?? I need to find the Equiv. Resistance of N pieces connected inparallel. I calculated that 1 piece is = R1*n^-1 and I know that Ineed to add all of these to get the R eq. but because its aconceptual question and I have no numbers I can't figure out away to express this. I've already tried to put
(R1*n^-1) as an answer but it tells me it the answerdoesn't contain the variable . Please help!!??
Explanation / Answer
If you have N identical resistors inparallel, the total resistance is just R /N . This is because... . 1 / Rtot = 1 /R + 1 / R + 1/ R + ... = N / R . Rtot = R / N . So in your case... resistance ofone piece = R1 /N . Resistance of N pieces inparallel = R1 /N2Related Questions
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