12.Two flat surfaces are exposed to a uniform, horizontalmagnetic field of magni

Question

12.Two flat surfaces are exposed to a uniform, horizontalmagnetic field of magnitude 0.49 T. When viewed edge-on, the firstsurface is tilted at an angle of 11° from the horizontal, and anet magnetic flux of 8.00 10-3 Wb passes through it. The same netmagnetic flux passes through the second surface. a.Determine thearea of the first surface. b.Find the smallest possible value for the area of the secondsurface.
12.Two flat surfaces are exposed to a uniform, horizontalmagnetic field of magnitude 0.49 T. When viewed edge-on, the firstsurface is tilted at an angle of 11° from the horizontal, and anet magnetic flux of 8.00 10-3 Wb passes through it. The same netmagnetic flux passes through the second surface. a.Determine thearea of the first surface. b.Find the smallest possible value for the area of the secondsurface.

Explanation / Answer

The flux density B = 0.49 T The flux = 8.00 Wb The angle is = 11` The equation of magnetic flux is = BA cos so Area will be A = / B / cos which will be8.00/0.49/cos 11 = 16.642 m2 As you stated the smallest possible value so greater the valueof cos the smaller the value The max value of cos is 1. So A = / B => 8.00 / 0.49 = 16.32 m2 Note: Please check the calculations As you stated the smallest possible value so greater the valueof cos the smaller the value The max value of cos is 1. So A = / B => 8.00 / 0.49 = 16.32 m2 Note: Please check the calculations

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