A 0.60-kg basketball is dropped out of the window that is6.4 m above the ground.
ID: 1667042 • Letter: A
Question
A 0.60-kg basketball is dropped out of the window that is6.4 m above the ground. The ball is caughtby a person whose hands are 1.3 m abovethe ground. (a) How much work is done by the ball by itsweight?1 J
(b) What is the gravitational potential energy of the basketball,relative to the ground when it is released?
2 J
(c)What is the gravitational potential energy of the basketballwhen it is caught?
3 J
(a) How much work is done by the ball by itsweight?
1 J
(b) What is the gravitational potential energy of the basketball,relative to the ground when it is released?
2 J
(c)What is the gravitational potential energy of the basketballwhen it is caught?
3 J
Explanation / Answer
a) work = force*distance =mg(6.4-1.3) =0.6(9.8)(5.1) = 29.988 J b) U = mgh = (0.6)(9.8)(6.4) = 37.632 J c) U = mgh = (0.6)(9.8)(1.3) = 7.644 J Hopefully this helps
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