Each second, the fuel burning in an electric power plantproduces 1000 MJ of heat
ID: 1667052 • Letter: E
Question
Each second, the fuel burning in an electric power plantproduces 1000 MJ of heat energy at a temperature of 527ºC andreleases waste heat into a cooling pond at 27ºC.(a)What is the maximum (Carnot) efficiency of the power plant?
(b)If the plant operates at half the maximum efficiency, what isthe power output of the plant?
(c)How much heat is rejected each second to the cooling pond eachsecond? Each second, the fuel burning in an electric power plantproduces 1000 MJ of heat energy at a temperature of 527ºC andreleases waste heat into a cooling pond at 27ºC.
(a)What is the maximum (Carnot) efficiency of the power plant?
(b)If the plant operates at half the maximum efficiency, what isthe power output of the plant?
(c)How much heat is rejected each second to the cooling pond eachsecond?
Explanation / Answer
Temperature of hot reservoir(source) T1 = 5270C = 527+ 273 = 800 K Temperature ofsink T2 = 270C = 27+ 273 = 300 K Inputpower Pin = 1000 MJ/ s = 1000 MW a. Carnotefficiency = 1 - (T2/ T1) = 1 - 300/ 800 = 0.625 = 62.5% b. Efficiency at half themaximumvalue ' = / 2 = 0.625/ 2 = 0.3125 Also = Outputpower / input power 0.3125 = Pout/ Pin Pout = 0.3125* 1000 MW = 312.5 MW c. Heat wasted persecond Prej = Pin - Pout Prej = 1000 - 312.5 = 678.50 MW = 678.5 MJ/ s Prej = 1000 - 312.5 = 678.50 MW = 678.5 MJ/ sRelated Questions
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