An electrically neutral model airplane is flying in ahorizontal circle on a 3.0-

Question

An electrically neutral model airplane is flying in ahorizontal circle on a 3.0-m guideline, which is nearly parallel tothe ground. The line breaks when the kinetic energy of the plane is50.0J. Reconsider the same situation, except that now there is apoint charge of +q on the plane and a point charge of -q at theother end of the guideline. In this case, the line breaks when thekinetic energy of the plane is 51.8J. Find the magnitude of thecharges. I'm confused where to start. An electrically neutral model airplane is flying in ahorizontal circle on a 3.0-m guideline, which is nearly parallel tothe ground. The line breaks when the kinetic energy of the plane is50.0J. Reconsider the same situation, except that now there is apoint charge of +q on the plane and a point charge of -q at theother end of the guideline. In this case, the line breaks when thekinetic energy of the plane is 51.8J. Find the magnitude of thecharges. I'm confused where to start.

Explanation / Answer

   The guide line breaks when centrifugal forceexceeds the maximum tension the line can bear. In case of unchargedplane, their is no force countering the centrifugal force whilecharged plane experience an inward force. It accounts for theincreased k.e. of plane when line snaps. Clearly this excess ink.e. is equal to the p.e. of charges at plane and other end ofguide line.    Change ink.e.   =   p.e. of chargecouple    + q and - q    (51.8   -   50.0)   J    =   -(1/40) * q1 * q2 /r    1.8   =   -9.0 * 109 * q * ( - q) / 3.0    q2   =   1.8* 3.0 / 9.0 * 109    charge   q   =   (6.0* 10-10)                      =   2.449* 10-5   C                       =   24.49   C    charge   q   =   (6.0* 10-10)                      =   2.449* 10-5   C                       =   24.49   C

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