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A block mass 1.6kg is attached to a horizontal spring that hasa force constant o

ID: 1667613 • Letter: A

Question

A block mass 1.6kg is attached to a horizontal spring that hasa force constant of 1000N. This spring is compressed 2.0 cm and is then released fromrest. a.)Calculate the speed of the block as it passes theequilibrium position x=0 if the surface is frictionless.b.)Calculate the speed of the block as it passes thruough theequilibrium position if a constant frictional force of 4.0N retardsits motion from the moment it is released. A block mass 1.6kg is attached to a horizontal spring that hasa force constant of 1000N. This spring is compressed 2.0 cm and is then released fromrest. a.)Calculate the speed of the block as it passes theequilibrium position x=0 if the surface is frictionless.b.)Calculate the speed of the block as it passes thruough theequilibrium position if a constant frictional force of 4.0N retardsits motion from the moment it is released.

Explanation / Answer

m=1.6kg, k=1000N/m (*force constant should be in N/m, but you haveN), and x=-2x10-2m a) v=? at x=0, so 1/2mv2=1/2kx2 ormv2=kx2 thenv=(kx2/m)=((1000)(-2x10-2)2/1.6)=.5 m/s b) Now we have 1/2kx2-fx=1/2mv2,kx2-2fx=mv2 and thenmv2=1000(-2x10-2)2-2(4)(2x10-2)=.24and then v= .387m/s

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