Goodmorning A person drives a car around a circular cloverleaf with aradius of 6
ID: 1667902 • Letter: G
Question
Goodmorning A person drives a car around a circular cloverleaf with aradius of 67 m at a uniform speed of 10 m/s. a) What is the acceleration of the car?______m/s^2 b) Compare this aanswer with the acceleration due to gravityas a percentage. ________% . ( can you please explain how you gotthis answer) c) Would you be able to sense the car's acceleration if youwere riding in it? What is the force of gravity between two 1255 kg carsseparated by a distance of 30 m on _______N How does this force compare with the weight of a car? Is it larger, smaller, or roughly the same? Goodmorning A person drives a car around a circular cloverleaf with aradius of 67 m at a uniform speed of 10 m/s. a) What is the acceleration of the car?______m/s^2 b) Compare this aanswer with the acceleration due to gravityas a percentage. ________% . ( can you please explain how you gotthis answer) c) Would you be able to sense the car's acceleration if youwere riding in it? What is the force of gravity between two 1255 kg carsseparated by a distance of 30 m on _______N How does this force compare with the weight of a car? Is it larger, smaller, or roughly the same?Explanation / Answer
Radius r= 67 m
Speed v= 10 m / s
(a). Accleration of the car a = v ^ 2/ r
= 1.492 m / s^ 2
(b). Required percentage = ( a/ g ) * 100 = ( 1.492 /9.8 ) * 100
= 15.229 %
©. Yes
(d). mass m = 1255 kg
Separation r= 30 m
Force of gravity F = Gm*m / r^ 2
Where G = gravitational constant = 6.67 * 10 ^ -11 N m^2 /kg^ 2
Plug the values we get F = 1.167 * 10^-7 N
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