A suspicious-looking manruns as fast as he can along a moving sidewalk from one
ID: 1668039 • Letter: A
Question
A suspicious-looking manruns as fast as he can along a moving sidewalk from one end to theother, taking 3.50 s. Then security agentsappear and the man runs as fast as he can back along the sidewalkto his starting point, taking 11.0 s. Whatis the ratio of the man's running speed to the sidewalk's speed?(running speed / sidewalk speed)1
A suspicious-looking manruns as fast as he can along a moving sidewalk from one end to theother, taking 3.50 s. Then security agentsappear and the man runs as fast as he can back along the sidewalkto his starting point, taking 11.0 s. Whatis the ratio of the man's running speed to the sidewalk's speed?(running speed / sidewalk speed)
1
A suspicious-looking manruns as fast as he can along a moving sidewalk from one end to theother, taking 3.50 s. Then security agentsappear and the man runs as fast as he can back along the sidewalkto his starting point, taking 11.0 s. Whatis the ratio of the man's running speed to the sidewalk's speed?(running speed / sidewalk speed)
1
A suspicious-looking manruns as fast as he can along a moving sidewalk from one end to theother, taking 3.50 s. Then security agentsappear and the man runs as fast as he can back along the sidewalkto his starting point, taking 11.0 s. Whatis the ratio of the man's running speed to the sidewalk's speed?(running speed / sidewalk speed)
1
A suspicious-looking manruns as fast as he can along a moving sidewalk from one end to theother, taking 3.50 s. Then security agentsappear and the man runs as fast as he can back along the sidewalkto his starting point, taking 11.0 s. Whatis the ratio of the man's running speed to the sidewalk's speed?(running speed / sidewalk speed)
1
A suspicious-looking manruns as fast as he can along a moving sidewalk from one end to theother, taking 3.50 s. Then security agentsappear and the man runs as fast as he can back along the sidewalkto his starting point, taking 11.0 s. Whatis the ratio of the man's running speed to the sidewalk's speed?(running speed / sidewalk speed)
1
A suspicious-looking manruns as fast as he can along a moving sidewalk from one end to theother, taking 3.50 s. Then security agentsappear and the man runs as fast as he can back along the sidewalkto his starting point, taking 11.0 s. Whatis the ratio of the man's running speed to the sidewalk's speed?(running speed / sidewalk speed)
1
Explanation / Answer
Let the man's speedbe vm and thatof sidewalk be vw. For the first part, effective speed ofman v1 = vm + vs For the second part effective speed ofman v2 = vm - vs also speed = distance(d) / time(t) => v1 = d/ 3.50 vm + vs = d/ 3.50 -------- (1) and v2 = d/ 11.0 vm - vs = d/11.0 --------(2) adding (1) and (2) 2 *vm = d/3.5 + d/ 11.0 = 14.5* d / 38.5 vm = 14.5* d /77 ---------(3) subtracting (2) from (1) 2 *vs = d/3.5 - d/ 11.0 = 7.5* d / 38.5 vs = 7.5* d /77 -----------(4) Dividing equation (3) by equation (4) vm /vs = (14.5 * d /77) /(7.5 * d / 77) = 29/15 also speed = distance(d) / time(t) => v1 = d/ 3.50 vm + vs = d/ 3.50 -------- (1) and v2 = d/ 11.0 vm - vs = d/11.0 --------(2) adding (1) and (2) 2 *vm = d/3.5 + d/ 11.0 = 14.5* d / 38.5 vm = 14.5* d /77 ---------(3) subtracting (2) from (1) 2 *vs = d/3.5 - d/ 11.0 = 7.5* d / 38.5 vs = 7.5* d /77 -----------(4) Dividing equation (3) by equation (4) vm /vs = (14.5 * d /77) /(7.5 * d / 77) = 29/15Related Questions
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