8. The following genotypes were observed in a small population: 28 AA, 24 Aa, 48

Question

8. The following genotypes were observed in a small population: 28 AA, 24 Aa, 48 aa. Calculate the inbreeding coefficient, assuming that inbreeding alone is responsible for any deviation from Hardy-Weinberg expectation. (3 points) 8. The following genotypes were observed in a small population: 28 AA, 24 Aa, 48 aa. Calculate the inbreeding coefficient, assuming that inbreeding alone is responsible for any deviation from Hardy-Weinberg expectation. (3 points) 8. The following genotypes were observed in a small population: 28 AA, 24 Aa, 48 aa. Calculate the inbreeding coefficient, assuming that inbreeding alone is responsible for any deviation from Hardy-Weinberg expectation. (3 points)

Explanation / Answer

AA Aa aa

28 24 48

here A = p

a= q

p+q = 1 =100%

Now as AA= 28 therefore number of alleles =2x28=56

Aa = 24 therefore number of alleles= 2x 24= 48

aa= 48 therefore alleles =2x 48= 96

total alleles= 56+48+96= 200

now

frequency of A= 56+24 = 80 = 80 divided by 200= 0.4

frequency of a = 1-0.4= 0.6

now the formula

F= no of expected number of heterogygous - no of obsereved heterogyzous divided by no of expected heterogyzous

now to find expected heterogyzous

Aa= 2x 0.4x0.6 = 0.48

so no of individual = 0.48x 100 = 48

no of observed heterogyzous = 24

finally

F= 48 -24 /48 = 24/48 = 0.5 ans

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