Question Details: Consider a person on the Moon who launches herself into astand

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Question Details: Consider a person on the Moon who launches herself into astanding broad jump at 45 degrees. The average force generatedduring launching is, as stated in the lecture delivered onFebruary 9, 2010, F=2W, and the distance overwhich this force acts is 60 cm. Kindly, computer: (a) the range ofthe jump; (b) the maximum height of the jump; (c) the duration ofthe jump.
Consider a person on the Moon who launches herself into astanding broad jump at 45 degrees. The average force generatedduring launching is, as stated in the lecture delivered onFebruary 9, 2010, F=2W, and the distance overwhich this force acts is 60 cm. Kindly, computer: (a) the range ofthe jump; (b) the maximum height of the jump; (c) the duration ofthe jump.

Explanation / Answer

I'm not sure I understand what F=2Wmeans. W could be watts but that's not a force that's a power unit.If you meant 2N as in Newtons then....

You still don't have enough information to solve the problem. Youneed the person's mass...consider if you push a 10 metric ton buswith a measly 2N over 60cm it is barely going to go anywhere but ifyou use a slingshot to do this with a small rock then you'll get areally long and high trajectory. Mass matters.

But assuming you have the mass then note that they give force anddistance over which it acts. What quantity is force times distance?How does this relate to mass and velocity?

Also consider potential energy on the moon. Remember its surfaceacceleration is quite close to 1/6 earth's 9.8 m/s^2.

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