Two identical massless springs are hung from a horizontal support. A block of ma

Question

Two identical massless springs are hung from a horizontal support. A block of mass 2.5 kg is suspended from the pair of springs, as shown. The acceleration of gravity is 9.8 m/s2. When the block is in equilibrium, each spring is stretched an additional 0.42 m. The force constant of each spring is most nearly k ? 29 N/m k ? 28 N/m k ? 120 N/m k ? 26 N/m k ? 12 N/m k ? 35 N/m k ? 86 N/m k ? 17 N/m k ? 19 N/m k ? 130 N/m

Explanation / Answer

total spring constant k = k1+k2 = 2k we know that      F = -kx ==> F = -2kx ==> 2k = F / x = mg /x = 2.5 * 9.8 / 0.42 = 58.33N/m For each spring k = 58.33/2 = 29.1 N/m

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