A 2170 kg railroad flatcar,which can move with negligible friction, is motionles
ID: 1668924 • Letter: A
Question
A 2170 kg railroad flatcar,which can move with negligible friction, is motionless next to aplatform. A 244 kg sumo wrestlerruns at 5.3 m/s along theplatform (parallel to the track) and then jumps onto the flatcar. (a) What is the speed of the flatcar if he then stands onit?m/s
(b) What is the speed of the flatcar if he then runsat 5.3 m/s relative to it in hisoriginal direction?
m/s
(c) What is the speed of the flatcar if he then turns and runsat 5.3 m/s relative to theflatcar opposite his original direction?
m/s
(a) What is the speed of the flatcar if he then stands onit?
m/s
(b) What is the speed of the flatcar if he then runsat 5.3 m/s relative to it in hisoriginal direction?
m/s
(c) What is the speed of the flatcar if he then turns and runsat 5.3 m/s relative to theflatcar opposite his original direction?
m/s
Explanation / Answer
(a) assumed that it is completely inelastic conservation 0f momentum: 244*5.3=(244+2170)*v =>the speed of the flatcar if he then stands on it v=0.536m/s (b)we continue using the conservation of momentum 244*5.3 =244*(5.3+v) *2147*v => v=0, the flatcaris stationary (c) the speed of the flatcar if he then turns and runsat 5.3 m/s relative to theflatcar opposite his original direction 244*5.3=244*(v-5.3) +2147*v => v=1.082m/sRelated Questions
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