(a) Find the speed of the 2 kg block after itfalls from rest a distance of 2.5 m

Question

(a) Find the speed of the 2 kg block after itfalls from rest a distance of 2.5 m.
1 m/s

(b) What is the angular velocity of the pulley at this time?
2 rad/s A 4 kg block resting on a frictionless horizontal ledge is attachedto a string that passes over a pulley and is attached to a hanging2 kg block. The pulley is a uniform disk of radius 7.0 cm and mass 0.20 kg. (a) Find the speed of the 2 kg block after itfalls from rest a distance of 2.5 m. (b) What is the angular velocity of the pulley at this time?

Explanation / Answer

Let T1,T2 be the tension of the rod in horizontal and verticalsegment we have : T1 =Ma mg -T2 =ma (T2-T1)R =(1/2)m'.R^2 .(a/R) => T2-T1 =(1/2)m'a sum up 3 equations=> mg =(M+m+m'/2).a => a= 3.21m/s2 => the speed of the 2 kg block after it falls from rest adistance of 2.5 m : V= (2aS) = 4 m/s b)the angular velocity at this time : =V/R = 57.14 rad/s

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