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acceleration 1 m/s 2 tension horizontal 2 N vertical 3 N acceleration 1 m/s 2 te

ID: 1668973 • Letter: A

Question

acceleration 1 m/s2 tension horizontal 2 N vertical 3 N acceleration 1 m/s2 tension horizontal 2 N vertical 3 N In the system shown below, there is a block of mass M =4.2 kg resting on a horizontal ledge. Thecoefficient of kinetic friction between the ledge and the block is0.25. The block is attached to a string that passes over a pulley,and the other end of the string is attached to a hanging block ofmass m = 2.2 kg. The pulley is auniform disk of radius 8.8 cm and mass0.63 kg. Find the acceleration of eachblock and the tensions in the segments of string between each blockand the pulley. acceleration 1 m/s2 tension horizontal 2 N vertical 3 N

Explanation / Answer

let T1 T2 is the tension of the string in horizontal andvertical let a is the acceleration of two blocks we have : T1 -Mg =Ma mg-T2 =ma (T2-T1)R = (1/2)m'R^2.(a/R) => T2-T1 =(1/2)m'a sum up 3 equation=> mg-Mg =(M+m+m/2')a => a =1.68 m/s2 => T1 = Ma+Mg = 17.346 N T2 = mg-ma = 17.864 N