The handle of a 27 kg lawnmower makes a37 degree angle with the horizontal. If t

Question

The handle of a 27 kg lawnmower makes a37 degree angle with the horizontal. If the coefficient of friction between lawnmower and ground is0.6, what magnitude of force is required to push the mower atconstant velocity? Assume the force is applied in the direction ofthe handle. The handle of a 27 kg lawnmower makes a37 degree angle with the horizontal. If the coefficient of friction between lawnmower and ground is0.6, what magnitude of force is required to push the mower atconstant velocity? Assume the force is applied in the direction ofthe handle.

Explanation / Answer

Create force equations to solve this, so in the y direction we have N-mg-FSin=0 and in the x direction we have Fcos-f=0 or FCos-N=0 then we solve for N in the first equation to get N=mg+FSin and we plug this into the second to get FCos-(mg+FSin)=0 or FCos-mg-FSin=0 then F(Cos-Sin)-mg=0 and finally F=(mg)/(Cos-Sin)=362.8N

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