find the electric field at (0,0) [ magnitude and direction]due to the following

Question

find the electric field at (0,0) [ magnitude and direction]due to the following charge distribution:    2C @ (1 , 1)    -1C @ (-2 , 3)    4C @ (0 , -3) find the electric field at (0,0) [ magnitude and direction]due to the following charge distribution:    2C @ (1 , 1)    -1C @ (-2 , 3)    4C @ (0 , -3)

Explanation / Answer

We know that        E = keQ /r2 So that when Q = 2C , r = 2 ==> E1 = 2ke / 2 = ke at Q = -1C , r = 4 ==> E2 = -ke / 16 at Q = 4C ==> E3 = 4ke / 9 Therefore electric field at (0,0) is            E = E1+ E2 + E3               = ke - ke/16 + 4ke/9               = ke [ 1 -0.0625 + 0.444]               = ( 9 x 109 ) * 1.3819               = 12.43 x 109 N/C

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