When a resistor is connected across the terminals of an ac generator (112 V) tha

Question

When a resistor is connected across the terminals of an ac generator (112 V) that has a fixed frequency, there is a current of 0.500 A in the resistor.  When an inductor is connected across the terminals of this generator, there is a current of 4.00 A in the inductor.  When both the resistor and the inductor are connected in series between the terminals of this generator, what are (a) the impedance of the series combination and (b) the phase angle between the current and the voltage of the generator?

Explanation / Answer

Vrms=I1*R=>0.5*R=112 => R=224 Ohm Vrms=I2*XL=>XL=112/4=28 ohm Z=sqrt(R^2+XL^2)=225.74 Ohm the angle is alpha=arctan(XL/R) =>alpha=7.125 degrees

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