Two parallel plates having charges of equal magnitude but oppositesign are separ

Question

Two parallel plates having charges of equal magnitude but oppositesign are separated by 12cm. Each plate has a charge densityof 36nC/m2. A proton is released from rest at thepositive plate.
Determine
a) The potential difference across the plates
b) The kinetic Energy of the proton when it reaches the negativeplate
c) The speed of the proton as it strikes the negative plate
d) the acceleration of the proton
e) the force acting on the proton

I know that I have to use a gaussian surface to find the charge,but I do not know how to set up the calculus to accomplish thistask. Any help is VERY appreciated.

Explanation / Answer

Two parallel plates having charges of equal magnitude but oppositesign are separated by 12cm. Each plate has a charge densityof 36nC/m2. A proton is released from rest at thepositive plate. Given that           = q /A = 36nC/m2            d = 12cm = 0.12 m Determine a) The potential difference across the plates              V = E d                  = ( / o ) * d                  = ( 36 x 10-9 / 8.85 x 10-12) * 0.12                  = 488 V b) The kinetic Energy of the proton when it reaches the negativeplate            KE = e V = 1.6 x 10-19 * 488 = 7.81 x10-17 J c) The speed of the proton as it strikes the negative plate                 v = 2KE / m                    = 2 * 7.81 x 10-17 / 1.67 x 10-27                    = 3.05 x 1010 m/s d) the acceleration of the proton          F = E e       ==> a = E e / m                 = ( / o) e / m                 = 36 x 10-9 * 1.6 x 10-19 / 8.85 x10-12 * 1.67 x 10-27                 = 3.897 x 1011 m/s2 e) the force acting on the proton            F = ma= 1.67 x 10-27 * 3.897 x 1011 = 18.37 x10-16 N

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.