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This is another gordon rule question Q#1 A hand exerts a constant horizontal for

ID: 1670818 • Letter: T

Question

This is another gordon rule question Q#1 A hand exerts a constant horizontal force on a block that isfree to slide on a frictionless surface. The block start from restat point A, and by the time it has travelled a distance to point B,it is travelling with a speed Vb. when the block has travelledanother distance to point C, will its speed be greater than, lessthan, or equel to 2vB? Explain in great detail your reasoning.Hint--- consider using the Work-Energy principle. This is another gordon rule question Q#1 A hand exerts a constant horizontal force on a block that isfree to slide on a frictionless surface. The block start from restat point A, and by the time it has travelled a distance to point B,it is travelling with a speed Vb. when the block has travelledanother distance to point C, will its speed be greater than, lessthan, or equel to 2vB? Explain in great detail your reasoning.Hint--- consider using the Work-Energy principle.

Explanation / Answer

   I suppose that distance AB and BC aresame.    According to work energyprinciple,   workdone   =   change in k.e. ofobject    Work done from A toB   WAB   =   F* d    where   d   =   distancebetween A and B    then   K   =   KB   -   KA    F *d   =   (1/2) * m *vb2   -   (1/2)* m * 02    F *d   =   (1/2) * m *vb2      -------------(1)    F *d   =   (1/2) * m *vb2      -------------(1)    vb   =   (2* F * d /m)         -------------(2)    Between    B and C    WBC   =   F* d    and      F* d   =    (1/2) * m *vc2   -   (1/2)* m * vb2                            =   (1/2)* m * vc2   -  F *d                        (from equation (1))          =>   2* F *d       =      (1/2)* m * vc2          vc   =   (4* F * d / m)      ----------(3)    Dividing equation (3) by equation (1)    vc /vb   =   (4 * F * d/ m) / (2 * F * d / m)                =   2   vc   =   vb* 2    hence the speed of object at C is less thantwice the speed of object at B.    vc   <   2* vb    hence the speed of object at C is less thantwice the speed of object at B.    vc   <   2* vb
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