MA = +RB(40ft) - (5k)(32ft) - (1k/ft)(40ft)(20ft) =0 RB = +24k MB = -RA(40ft) +
ID: 1671057 • Letter: M
Question
MA = +RB(40ft) - (5k)(32ft) - (1k/ft)(40ft)(20ft) =0 RB = +24k MB = -RA(40ft) + (5k)(8ft) + (1k/ft)(40ft)(20ft) =0 RA = +21k 1) could you explain how the math works inoder to solve thisequation as well why is RB subtraction and RA addition. Is thatalways the case? MA = +RB(40ft) - (5k)(32ft) - (1k/ft)(40ft)(20ft) =0 RB = +24k MB = -RA(40ft) + (5k)(8ft) + (1k/ft)(40ft)(20ft) =0 RA = +21k 1) could you explain how the math works inoder to solve thisequation as well why is RB subtraction and RA addition. Is thatalways the case?Explanation / Answer
MA = +RB(40ft) - (5k)(32ft) - (1k/ft)(40ft)(20ft) =0
RB(40ft) - (5k)(32ft) - (1k/ft)(40ft)(20ft) = 0
RB(40ft) = (5k)(32ft) + (1k/ft)(40ft)(20ft)
RB = [(5k)(32ft) + (1k/ft)(40ft)(20ft)] / 40ft
= [ 4 k + 20k ]
= 24k
MB = -RA(40ft) + (5k)(8ft) + (1k/ft)(40ft)(20ft)= 0
-RA(40ft) + (5k)(8ft) + (1k/ft)(40ft)(20ft) = 0
RA(40ft) = (5k)(8ft) + (1k/ft)(40ft)(20ft)
RA = [(5k)(8ft) + (1k/ft)(40ft)(20ft)] / (40ft)
= [ 1k + 20k]
= +21k
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