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(a) Find the maximum value of for which the refracted ray will undergo total int

ID: 1671082 • Letter: #

Question

(a) Find the maximum value of for which the refracted ray will undergo total internal reflectionat the left vertical face of the block.


(b) Repeat the calculation for the case in which the fluorite block is immersed in ethylalcohol.


(c) What happens if the block is immersed in carbon disulfide?
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Explanation / Answer

(a) Find the maximum value of for which therefracted ray will undergo total internal reflection at the leftvertical face of the block.        Refractive index of fluorite = 1.433              The minimum angle       sinc = n2 * sin90 / n1          = 1 /1.433       ==> c = 44.25o (b) Repeat the calculation for the case in which the fluorite block is immersed in ethylalcohol.       For ethyl alcohol n2 = 1.361               The minimum angle       sinc = n2 * sin90 / n1          =1.361 / 1.433       ==> c = 71.60o (c) The critical angle is more than 90o.