A concave lens refracts parallel rays in such a way that they are bent away from

Question

A concave lens refracts parallel rays in such a way that they are bent away from the axis of the lens. For this reason, a concave lens is referred to as a diverging lens. If the focal length of the concave lens is -7.50 cm, at what distance d0 from the lens should an object be placed so that its image is formed 3.70 cm from the lens? Express your answer in centimeters. What is the magnification m produced by the concave lens described in Part B? Express your answer numerically to two significant figures. Where should the object be moved to have a larger magnification? The object should be moved closer to the lens. The object should be moved farther from the lens. The object should be moved to the focal point of the lens. The object should not be moved closer to the lens than the focal point.

Explanation / Answer

we know that    1 / f   = 1 / di + 1 / do Given that       f = - 7.50 cm      di = 3.70 cm Therefore we have     1 / do = 1 / f - 1 / di               = (di - f) / f * di ==> do = f * di / ( di - f ) = -7.50 *3.70 / (3.70 - -7.50) = - 2.477 cm magnification m = - do / di = - (-2.477) /3.70 = 0.6696 Object should be move closer to focal point.

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