water flows through a pipe. The velocity v2 is 15 m/s. What is the cross-section

Question

water flows through a pipe. The velocity v2 is 15 m/s. What is the cross-sectional area of the pipe in region 2? What is the water pressure in region 2?

Explanation / Answer

a) According to equation of continuity we have            A1v1 = A2v2         ==> A2 = A1 v1 /v2                      = 20 * 10 / 15                      = 13.33 cm2 b) The pressure at region 2 is          P1 +0.5v12 = P2 +0.5v22 + gh          P1 - P2 =0.5 [ v22 - v12 +2gh ]                      = 0.5 * 1000 [ 225 - 100 + 117.6 ]          P1 - P2 = 121300           P2 = P1 -121.3 kPa                = 400kPa - 121.3 kPa                = 278.7 kPa

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