(a) Calculate the charge on the positive plate of the capacitorjust after the sw

Question

(a) Calculate the charge on the positive plate of the capacitorjust after the switch is closed.

Q(0+) = C    

(b) Calculate the following currents immediately after theswitch is closed.

I1(0+) = A   

I2(0+) = A    

(c) After the switch has been closed for a long time, calculatethe following quantities.

I1 = A   

I2 = A   

Q = C    

(d) At some yet later time T, the switch is againopened. Calculate the following currents immediatelyafterward.

I1(T+) = A   

I3(T+) = A    

(e) What is the time constant of the dischargingcircuit?

t =

Explanation / Answer

a, Q(0+)=0 b,I1(0+)=E/R1=0.12A I2(0+)=0 c, I1=I2=E/(R1+R2)=0.042A Q=V*C=E*R2/(R1+R2)*C=5*79/(79+41)*10*10^-6=3.29*10^-5 C d, I1(T+)=0 I3(T+)=(Q(T)/C)/R2 e, t=R1*R2*C/(R1+R2)=2.7*10^-4 s

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