2. A wind whose average force is 75N blowsperpendicular to a windmill at a point

Question

   2. A wind whose average force is 75N blowsperpendicular to a windmill at a point 1.5m from its center. hemoment of inertia of the windmill is 32 kg*m^2. Assume no frictionat the axle. a. Find the average torque on the windmill due to thisforce. b. Find the angular acceleration of the windmill. c. Find its angular velocity after 5s if it started at rest 1)in rad/sce 2) in rev/min.    2. A wind whose average force is 75N blowsperpendicular to a windmill at a point 1.5m from its center. hemoment of inertia of the windmill is 32 kg*m^2. Assume no frictionat the axle. a. Find the average torque on the windmill due to thisforce. b. Find the angular acceleration of the windmill. c. Find its angular velocity after 5s if it started at rest 1)in rad/sce 2) in rev/min.

Explanation / Answer

force F = 75 N distance r= 1.5 m Moment of inertia I = 32 kg m^ 2 (a). Average torque T = Fr                                   = 112.5 N m (b).Angular accleration = T / I                                       =3.515 rad / s ^ 2 (c). Initial angular speed w= 0 time t= 5 s angular speed after time t is w ' = w + t                                                 = 0 + 17.57 = 17.57 rad / s                                                 = 17.57 * ( 1/ 2 ) rev / ( 1/ 60 ) min                                                 = 167.85 rev / min

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