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magnitude 3 V/m direction 4---Select---from a to bradially outwardradially inwar

ID: 1672317 • Letter: M

Question

magnitude 3 V/m direction 4---Select---from a to bradially outwardradially inwardfrom b to a In the figure below a conducting rod of length L =42.5 cm moves in a magnetic field B of magnitude 0.450 T directed into the plane of the figure. The rod moves with speed v = 3.00 m/sin the direction shown. (Assume the rod has no appreciable thickness.) (a) What is the potential difference between the ends of the rod? 1 V (b) Which point, a or b, is at higher potential? point a Point b (c) When the charges in the rod are in equilibrium, what are the magnitude and direction of the electric field within the rod? magnitude 3 V/m direction 4 (d) When the charges in the rod are in equilibrium, which point, a or b, has an excess of positive charge? point a Point b (e) What is the potential difference across the rod if it moves parallel to ab? 6 V What is the potential difference across the rod if it moves directly out of the page? 7 V

Explanation / Answer

(a) What is the potential difference betweenthe ends of the rod?
emf = B v L = 0.57 V

(b) Which point, a or b, is at higherpotential?
2 pointb    
(c) When the charges in the rod are in equilibrium, what are themagnitude and direction of the electric field within the rod?
magnitude = emf/L = 1.35 V/m direction from b to a

(d) When the charges in the rod are in equilibrium, which point,a or b, has an excess of positive charge?
5 pointb    
(e) What is the potential difference across the rod if it movesparallel to ab?
emf = 0 V

What is the potential difference across the rod if it movesdirectly out of the page?
emf =0 V 2 pointb     2 pointb     2 5 pointb     5 pointb     5 magnitude = emf/L = 1.35 V/m direction from b to a