***WILL GIVE LIFESAVER FOR CORRECT ANSWERS***:) A circuit is constructed from tw

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***WILL GIVE LIFESAVER FOR CORRECT ANSWERS***:)    A circuit is constructed from two batteries and two wires, asshown in the diagram below. Each battery has an emf of 1.7 volts. Each wire is 25 cmlong, and has a diameter of 0.0007 meters. The wires are madeof a metal which has 7e+28 mobile electrons per cubic meter; theelectron mobility is 6e-05 (m/s) / (V/m).  A steadycurrent runs through the circuit. The locations marked by "x"and labeled by a letter are in the the interior of thewire. Which of these statements (A, B, C) about the electricfield in the interior of the wires, at the locations marked by"x"s, are true? Check all that apply. A. The magnitude of the electric field at location G islarger than the magnitude of the electric field at locationF. B. At location D the electric field points to theright. C. At every marked location the magnitude of theelectric field is the same. Which of the following equations (A, B, C, D, E, F, G) isa correct energy conservation (round-trip potential difference)equation for this circuit, along a round trip path starting at thenegative end of battery #1 and traveling counterclockwise throughthe circuit (that is, traveling to the left through the battery,and continuing on around the circuit in the same direction)? A. +1.7V - E*(0.25m) = 0 B. -1.7V + E*(0.25m) + 1.7V - E*(0.25m) = 0 C. +1.7V - E*(0.25m) + 1.7V - E*(0.25m) = 0 D. -1.7V + E*(0.25m) - 1.7V + E*(0.25m) = 0 E. -1.7V + E*(0.25m) = 0 F. +1.7V - E*(0.25m) - 1.7V + E*(0.25m) = 0 G. +1.7V - 1.7V =0 What is the magnitude of the electric field at locationG? How many electrons per second enter the positive end ofbattery #2? __________ electrons/s If the cross-sectional area of both wires were increased by afactor of 4, what would be the magnitude of the electric field atlocation G? Which of the diagrams below best shows the approximatedistribution of excess charge on the surface of the circuit?

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I would really really appreciate help with the answers to this question.  It is due tonight before midnight PST!  I will reward with lifesaver rating!!

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