what is the solution to these problems? A container is placed in a water bath an

Question

what is the solution to these problems? A container is placed in a water bath and held at constantvolume as a mixture of fuel and oxygen is burned inside it. Thetemperature of the water is observed to rise during the burning(the water is also held at constant volume). (a) Consider the burning mixture to be thesystem. What are the signs of the following?
Q 1---Select---positivenegativezero U 2---Select---positivenegativezero W 3---Select---positivenegativezero
(b) What are the signs of these quantities if the water bath isconsidered to be the system?
Q 4---Select---positivenegativezero U 5---Select---positivenegativezero W 6---Select---positivenegativezero what is the solution to these problems? A container is placed in a water bath and held at constantvolume as a mixture of fuel and oxygen is burned inside it. Thetemperature of the water is observed to rise during the burning(the water is also held at constant volume). (a) Consider the burning mixture to be thesystem. What are the signs of the following?
Q 1---Select---positivenegativezero U 2---Select---positivenegativezero W 3---Select---positivenegativezero
(b) What are the signs of these quantities if the water bath isconsidered to be the system?
Q 4---Select---positivenegativezero U 5---Select---positivenegativezero W 6---Select---positivenegativezero (a) Consider the burning mixture to be thesystem. What are the signs of the following?
Q 1---Select---positivenegativezero U 2---Select---positivenegativezero W 3---Select---positivenegativezero
(b) What are the signs of these quantities if the water bath isconsidered to be the system?
Q 4---Select---positivenegativezero U 5---Select---positivenegativezero W 6---Select---positivenegativezero Q 1---Select---positivenegativezero U 2---Select---positivenegativezero W 3---Select---positivenegativezero

Explanation / Answer

(a)     because the volume is hels constant     W = 0     energy is transferred by heat from the burningmixture so     Q < 0     the first law then gives that     U = Q + W           = Q     U < 0 (b) again since volume is constant W = 0     energy is transferred by heat from the burningmixture to the water so     Q > 0     the first law then gives that     U = Q + W           = Q     U > 0

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