(a) What is the magnitude of F when the crate is in this final position? 1 N (b)
ID: 1673161 • Letter: #
Question
(a) What is the magnitude of Fwhen the crate is in this final position?1 N
(b) During the crate's displacement, what is the total work done onit?
2 J
(c) During the crate's displacement, what is the work done by theweight of the crate?
3 kJ
(d) During the crate's displacement, what is the work done by thepull on the crate from the rope?
4 J
(e) Knowing that the crate is motionless before and after itsdisplacement, use the answers to (b), (c), and (d) to find the workyour force F does on the crate.
5 kJ
(f) Why is the work of your force not equal to the product of thehorizontal displacement and the answer to (a)?
6
Explanation / Answer
From the figure the angle is =Sin-1( 4.0m / 12.m) = 19.5o The tension in the ropeis T = 240kg (9.8) /Cos19.5o = 2495N The force F = (2495N )Sin19.5 = 832.85 N b) there is no change in kinetic energy the total workdone is zero. c) The work done by the gravitational force is Wg = - m g L [ 1 - Cos19.5] =(240) (9.8) [ 1 - cos19.5] = - 1618.88J d)here the angle is 90 W = 0 e) The work done by the force is W = - Wg = 1618.8J From the figure the angle is =Sin-1( 4.0m / 12.m) = 19.5o The tension in the ropeis T = 240kg (9.8) /Cos19.5o = 2495N The force F = (2495N )Sin19.5 = 832.85 N b) there is no change in kinetic energy the total workdone is zero. c) The work done by the gravitational force is Wg = - m g L [ 1 - Cos19.5] =(240) (9.8) [ 1 - cos19.5] = - 1618.88J d)here the angle is 90 W = 0 e) The work done by the force is W = - Wg = 1618.8J e) The work done by the force is W = - Wg = 1618.8JRelated Questions
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